We express ((cos 2theta -i sin 2theta)^(...

We express `((cos 2theta -i sin 2theta)^(4) (cos 4theta + i sin 4 theta)^(-5))/((cos 3theta + i sin 3theta)^(-2) (cos 3theta -i sin 3theta)^(-9))` in the form of `x+iy`, we get

A

`cos 49theta-i sin 49 theta`

B

`cos 23theta- i sin 23theta`

C

`cos 49theta+ i sin 49theta`

D

`cos 21theta+ i sin 21theta`

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The correct Answer is:

A

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