The sum of the first n terms of the seri...

The sum of the first n terms of the series `1^(2)+2xx2^(2)+ 3^(2)+2xx4^(2)+ 5^(2)+2 xx6^(2) + cdots` is [ n(n+1)^(2)]^(//2) ` when n is even . When n is odd the sum is

A

`(3n(n+1))/(2)`

B

`(n^(2)(n+1))/(2)`

C

`(n(n+1)^(2))/(4)`

D

`[(n(n+1))/(2)]^(2)`

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The correct Answer is:

B

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