Prove that
`(1+sintheta-cos theta)/(1+sin theta+costheta)=tantheta//2`

Given that 1-costheta=2sin^2(theta/2) and 1+costheta=2cos^2(theta/2) prove that (1+sintheta-costheta)/(1+sintheta+costheta)=tan(theta/2)

Prove that (1+sin2theta+cos2theta)/(1+sin2theta-cos2theta)=cottheta

Prove that sin (3theta)/(1+2cos 2theta)=sin theta .

Prove that (sin2theta)/(1+cos2theta)=tantheta

Prove that (1+costheta+sintheta)/(1-costheta+sintheta)=cot(theta/2)

Solve sin2theta+costheta=0

Prove that (sin2theta)/(1-cos2theta)=cottheta

Prove that (1+sec2theta)(1+sec4theta)(1+sec8theta)=(tan8theta)/(tantheta)

Prove that (1 - cos 4theta)/(1 - cos 5theta) = [(sin (2theta))/(sin(5/2theta))]^2