If sinx +"cosec"x=2, then sin^(n)x+"cos...

If `sinx +"cosec"x=2`, then `sin^(n)x+"cosec"^(n)x` is equal to .

A

2

B

`2^(n)`

C

`2^(n-1)`

D

`2^(n-2)`

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The correct Answer is:

A

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