Let P={theta:sintheta-costheta=sqrt(2)c...

Let `P={theta:sintheta-costheta=sqrt(2)costheta}andQ={theta:sintheta+costheta=sqrt(2)sintheta}` be two sets . Then

A

`PsubQand-Pnephi`

B

`Qcancel(sub)P`

C

`Pcancel(sub)Q`

D

P=Q

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The correct Answer is:

D

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