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If costheta(1)=costheta(2), then tan(...

If `costheta_(1)=costheta_(2)`, then `tan(theta_(1)-theta_(2))/(2)"tan"(theta_(1)+theta_(2))/(2)` is equal to

A

`(1)/(3)`

B

`-(1)/(3)`

C

1

D

`-1`

Text Solution

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The correct Answer is:
B
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