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If sinalpha+sinbeta=andcosalpha+cosbeta...

If `sinalpha+sinbeta=andcosalpha+cosbeta=b` , then the value of `"tan"(alpha-beta)/(2)` is

A

`+-sqrt((4-a^(2)-b^(2))/(a^(2)-b^(2)))`

B

`+-sqrt((2-a^(2)-b^(2))/(a^(2)+b^(2)))`

C

`+-sqrt((a^(2)-b^(2))/(4+a^(2)+b^(2)))`

D

`+-sqrt((4-a^(2)-b^(2))/(a^(2)+b^(2)))`

Text Solution

Verified by Experts

The correct Answer is:
D
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