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If the pair of lines ax^2 + 2(a + b)xy +...

If the pair of lines `ax^2 + 2(a + b)xy + by^2 = 0` lie along the diameters of a circle and divide the circle into four sectors such that the area of one of the sectors is thrice the area of another sector, then

A

`3a^2 - 10ab+3b^2 = 0`

B

`3a^2- 2ab +-3b^2 = 0`

C

`3a^2 + 10ab +3b^2 = 0`

D

`3a^2 + 2ab + 3b^2 =0`

Text Solution

Verified by Experts

The correct Answer is:
D
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