Home
Class 11
MATHS
The equation of the circle which has nor...

The equation of the circle which has normal `( x -1) ( y - 2) =0 ` and a tangent `3 x + 4y = 6` is

A

` x^(2) +y^(2) - 2x - 4y + 4 = 0`

B

`x^(2) +y^(2) - 2x - 4y + 5 = 0`

C

`x^(2) + y^(2) = 5`

D

`( x - 3)^(2) + (y - 4)^(2) = 5`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

The equation of the circle which touches the lines x=0, y=0 and 4x + 3y =12 is

The equation of the circle is 3x^(2) + 3y^(2)+6x-4y -1=0 . Then its radius is

The equation of the circle with centre at (1,1) and touching the line 3x+4y+3=0 is

Find the equation of the line which is equidistant from the parallel lines 9x + 6y - 7 = 0 and 3x + 2y + 6 = 0

If the equations of the tangent to the circle x^(2)+ y^(2)- 2x + 6y -6 =0 parallel to 3x - 4y + 7=0 is 3x - 4y +k=0 , then the values of k are : a) 5,-35 b) -5,35 c) 7,-32 d) -7,32

The parametric equations of the circle x^(2) + y^(2) + x + sqrt(3)y = 0 are

The equation of the tangent to y=-2x^(2)+3 at x=1 is