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A foot of the normal from the point (4,3...

A foot of the normal from the point (4,3) to a circle is (2,1) and a diameter of the circle has the equation `2x - y = 2 ` Then the equation of the circle is

A

`x^(2) +y^(2) +2x -1 = 0`

B

` x^(2) +y^(2) - 2x - 1=0`

C

` x^(2) +y^(2) - 2y - 1 = 0`

D

None of these

Text Solution

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The correct Answer is:
B
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