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A circle is given by x^(2) + (y - 1) ^(...

A circle is given by ` x^(2) + (y - 1) ^(2) = 1 ` . Another circle C touches it externally and also the x - axis. Then the locus of its center is

A

`{(x,y): x^(2) = 4y }cup {(x,y):y le 0}`

B

`{(x,y):x^(2)+(y-1)^(2) = 4} cup {(x,y): y le 0}`

C

`{(x,y):x^(2)= y } cup {(0,y):y le 0}`

D

`{(x,y):x^(2)=4y}cup{(0,y):y le 0}`

Text Solution

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The correct Answer is:
D
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