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The centre of the circle S = 0 lies on t...

The centre of the circle S = 0 lies on the line ` 2x - 2y + 9 = 0 and S = 0 ` cuts orthogonally the circle ` x^(2) + y^(2) = 4` . Then the circle s = 0 passes through two fixed points, which lie on

A

x = y

B

x + y = 0

C

x - 2y = 0

D

x + 2y = 0

Text Solution

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The correct Answer is:
B
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