The locus of the foot of perpendicular d...

The locus of the foot of perpendicular drawn from the centre of the ellipse `x^(2) + 3y^2 = 6` on any tangent to it is

A

`(x^2 - y^2)^(2)=6x^(2)+2y^2`

B

`(x^2 - y^2)^(2)=6x^(2)-2y^2`

C

`(x^2 + y^2)^(2)=6x^(2)+2y^2`

D

`(x^2 + y^2)^(2)=6x^(2)-2y^2`

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The correct Answer is:

C

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