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lim(xrarr0)((2^(sinx)-1)[loge(1+sin2x)])...

`lim_(xrarr0)((2^(sinx)-1)[log_e(1+sin2x)])/(x tan^(-1)x)` is equal to

A

`log_(e) 2`

B

`2log_e2`

C

`(log_e2)^(2)`

D

0

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The correct Answer is:
B
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