Find the values of `x, y, z`, if the matrix `A=[[0, 2 y, z],[ x, y, -z],[ x, -y, z]]` satisfy the equation `A^' A=I`

Find the value of x,y and z from the equation: [[4,3],[x,5]]=[[y,z],[1,5]]

Find the value of x,y and z from the equation: [[x+y+z], [x+z],[y+z]]=[[9],[5],[7]]

Find the values of x, y,z from the following equations i) [[4, 3 ], [x, 5]]=[[y , z], [1 , 5]] ii) [[x+y , 2] , [5+z, x y]]=[[6 , 2] , [5, 8]] iii) [[x+y+z], [x+z] , [y+z]]=[[9] , [5 ] ,[7]]

Find the values of x,y,z respectively, if [(x),(-y+z),(x-y-z)]=[(3),(5),(0)]

If x, y, z are non zero real numbers, then find the inverse of matrix A=[[x, 0, 0],[ 0, y, 0],[ 0, 0, z]] .

If (x,y,z) is the solution of the equations x - y - 2z = 3 2x + y + 4z = 5 4x - y - 2z = 11 then the value ofy equals

Consider the following system of linear equations, x+y+z=6 , x-y+z=2 , 2x+y+z=1 Find the value of x,y and z satisfying the above equation.

Find x, y, z and w if [[x-y, 2x+z],[2x-y, 3z+w]]=[[-1,5],[0,13]]

Write the value of x+y+z , if [(1,0,0),(0,1,0),(0,0,1)][(x),(y),(z)]=[(1),(-1),(0)]

Solve the system of equations using matrix method. 2 x+y+z=1 , x-2 y-z=3/2, 3 y-5 z=9