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If A = (a(ij))(nxxn) and f is a function...

If `A = (a_(ij))_(nxxn)` and f is a function, we define `f(A)= (f(a_(ij)))_(nxxn)`
Let `A=[(pi//2-theta,theta),(-theta,pi//2-theta)]`, then

A

sin A = cos A

B

sin A is invertible

C

sin A is not orthogonal

D

sin (2A) =2 sin A cos A

Text Solution

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The correct Answer is:
B
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