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theta=tan^(-1)(2 tan^2theta)-tan^(-1)(1/...

`theta=tan^(-1)(2 tan^2theta)-tan^(-1)(1/3tan theta)` then `tan theta =` a)`-2` b)`-1` c)`2//3` d)2

A

`-2`

B

`-1`

C

`2//3`

D

2

Text Solution

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The correct Answer is:
A
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