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2tan^(-1)[sqrt((a-b)/(a+b))tan ""theta/2...

`2tan^(-1)[sqrt((a-b)/(a+b))tan ""theta/2]=` a)`cos^(-1)((a cos theta + b)/(a+bcos theta))` b)`cos^(-1)((a+b cos theta)/(acos theta+b))` c)`cos^(-1)((acos theta)/(a+bcos theta))` d)`cos^(-1)((bcos theta)/(acos theta+b))`

A

`cos^(-1)((a cos theta + b)/(a+bcos theta))`

B

`cos^(-1)((a+b cos theta)/(acos theta+b))`

C

`cos^(-1)((acos theta)/(a+bcos theta))`

D

`cos^(-1)((bcos theta)/(acos theta+b))`

Text Solution

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The correct Answer is:
A
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