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tan[pi/4+1/2 cos^(-1)""a/b]+tan [pi/4-1/...

`tan[pi/4+1/2 cos^(-1)""a/b]+tan [pi/4-1/2cos^(-1)""a/b]`=a)`(2a)/b` b)`(2b)/a` c)`a/b` d)`b/a`

A

`(2a)/b`

B

`(2b)/a`

C

`a/b`

D

`b/a`

Text Solution

Verified by Experts

The correct Answer is:
B
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