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int4sinx*"cos"(x)/(2)*"cos"(3x)/(2)dx is...

`int4sinx*"cos"(x)/(2)*"cos"(3x)/(2)dx` is equal to

A

a) `cosx+1/2cos2x-1/3cos3x+C`

B

b) `cosx-1/2cos2x-1/3cos3x+C`

C

c) `cosx+1/2cos2x+1/3cos3x+C`

D

d) `cosx-1/2cos2x+1/3cos3x+C`

Text Solution

Verified by Experts

The correct Answer is:
B
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