int(cos2x)/(cosx)dx is equal to...

`int(cos2x)/(cosx)dx` is equal to

A

`2sinx+log(secx-tanx)+C`

B

`2sinx-log(secx-tanx)+C`

C

`2sinx+log(secx+tanx)+C`

D

`2sinx-log(secx+tanx)+C`

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The correct Answer is:

D

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