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If int(cos4x+1)/(cotx-tanx)dx=Acos4x+B, ...

If `int(cos4x+1)/(cotx-tanx)dx=Acos4x+B`, then

A

`A=-1//2`

B

`A=-1//8`

C

`A=-1//4`

D

None of these

Text Solution

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The correct Answer is:
B
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