Find the equation of tangent to `y=int_(x^(2))^(x^(3))(dt)/(sqrt(1+t^(2)))` at `x=1`.

The equation of the tangent to y=-2x^(2)+3 at x=1 is

Find the equation of the tangent to the curve y=3x^2 at (1,1)

Find the equation of the tangent to the curve x^(2/3)+y^(2/3)=2 at (1,1).

The solution for x of the equation int_(sqrt(2))^(x)(dt)/(sqrt(t^(2)-1))=pi/2 is a) pi b) (sqrt(3))/(2) c) 2sqrt(2) d)None of these

Find the equation of the tangent to the curve y=(x-7)/((x-2)(x-3)) at the point where it cuts the x -axis.

The equation of the tangent to the curve y=(1+x)^(y)+sin^(-1)(sin^(2)x) at x = 0 is :a) x-y+1=0 b) x+y+1=0 c) 2x-y+1=0 d) x+2y+2=0

If y=int_(x^(2))^(x^(3))(1)/(logt) dt(where xgt0 ), then find (dy)/(dx) .

Find the slope of the tangent to the curve y=(x-2)^2 at x=1