If g(x)=int(0)^(x)cos^(4)tdt, then g(x+p...

If `g(x)=int_(0)^(x)cos^(4)tdt`, then `g(x+pi)` equals

A

`(g(x))/(g(pi))`

B

`g(x)+g(pi)`

C

`g(x)-g(pi)`

D

`g(x)*g(pi)`

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The correct Answer is:

B

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