A tuning fork of frequency `f_(0)` moves away from you with a speed `v`, you hear a frequency `f_(1)`. When the tuning fork is stationary and you move away from tuning fork with same speed v a frequency `f_(2)` is heard. Then `(f_(1))/(f_(2))=`

Options

A. `v/c`
B. `(v+c)/(c-v)`
C. `(c^(2))/(c^(2)-v^(2))`
D. `(c-v)/(c+v)`

Answer

C

Explanation

`f_(1)=f_(0)((c)/(c+v)),f_(2)=f_(0)((c-v)/(c))`