A particle of mass m moving with a velocity `(3 hati + 2hatj) ms^(-1)` collides with a stationary body of mass M and finally moves with a velocity `(-2 hati + hatj)ms^(-1)`.If `m/M = 1/13` is then

Options

A. the impulse received by `M `is `m(hati + 5hatj)`
B. the velocity of the `M`is `(hati + 5hatj)`
C. the coefficient of restitution is `22/13`
D. All of the above are correct

Answer

B

Explanation

Impulse received by m
`J = m (v_f - v_i) = m (-2hati + hatj - 3hati - 2hatj) = m(-5hati - hatj)`
and impulse received by `M = - J = m(5hati + hatj)`
(b) `Mv = m(5hati + hatj) " or " v = m/M (5hati + hatj) = 1/13 (5 hati + hatj)`