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A body of mass m moving with a certain s...

A body of mass m moving with a certain speed suffers an inelastic collision with a body of mass M at rest. The ratio of the final kinetic energy of the system to the initial kinetic energy is

A

`m/(m + M)`

B

`M/(m + M)`

C

`(m + M)/m`

D

`(m + M)/M`

Text Solution

Verified by Experts

The correct Answer is:
A

Initial momentum of the system=mv, since body of mass M is at rest. After the inelastic collion, the bodies stick together and the mass of the composite body is (m+M). IfV is the speed of the composite body, its momentum will be (m+M)V. From the principle of conservation of momentum
we have , `mv = (m + M)V " or " V = ((m)/(m + M))v`
Intial K.E. = `1//2 mv^2 ` Final KE = `1//2 (m + M) V^2`
`("Final KE")/("Intial KE") = ((m + M)V^2)/(mv^2) = m/(m + M) [because V = ((m)/(m + M))v]`
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