A shell of mass 4 kg, initially at rest explodes into three fragments. Two of the fragments, each of mass 1 kg are found to move with a speed of `2 ms^(-1)` each in mutually perpendicular directions. Find the total energy (in joule) released in the explosion.

Explanation

Refer to the given figure `p_1 = 1 kg xx 2 m//s = 2 kg ms^(-1), p_2 = p_1 = 2 kg m//s`
`p = sqrt(p_1^2 + p_2^2) implies 2sqrt(2) kg ms^(-1)`
From conservation of momentum, we have,`vecp_3 + vecp =0 " " therefore p_3 = - p implies -2sqrt(2) kg . ms^(-1)`
Total energy released,= `1/2 xx 1 xx (2)^2 + 1/2 xx 1 xx (2)^2 + 1/2 xx 2 xx (-sqrt(2))^2 = 2 + 2 + 2 = 6 J`