The length of germanium rod is 0.928 cm and its area of cross-section is 1 `mm^2`. If for germanium `n_i=2.5xx10^(19)m^(-3),mu_h=0.19m^2V^(-1)s^(-1),mu_e=0.39m^2V^(-1)s^(-1)`, find its resistance.

Options

A. `2.5kOmega`
B. `4.0kOmega`
C. `5.0kOmega`
D. `10.0kOmega`

Answer

B

Explanation

We have, `R=(rhol)/A=L/(n_ie(mu_e+mu_h)A)=(0.928xx10^(-2))/(2.5xx10^(19)xx1.6xx10^(-19)(0.39+0.19)xx10^(-6))=4000Omega`