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A bar magnet A of magnetic moment M(A) ...

A bar magnet A of magnetic moment `M_(A)` is found to oscillate at a frequency twice that of magnet B of magnetic moment `M_(B)` when placed in a vibration magnetometer. `M_(A) and M_(B)` are related as

A

`M_(A)=2M_(B)`

B

`M_(A)=8M_(B)`

C

`M_(A)=4M_(B)`

D

`M_(A)=(1)/(8)M_(B)`

Text Solution

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The correct Answer is:
C

`(T_(A))/(T_(B))=sqrt((M_(B))/(M_(A)))rArr ("Freq. of B")/("Freq. of A")=(1)/(2), :. M_(A)=4M_(B)`
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