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An electron is revolving in an orbit of ...

An electron is revolving in an orbit of radius `5.0 xx 10^(-11)`m with a speed of `2.0 xx10^(4)` m/s. The magnetic moment associated with the atom will be

A

`12xx10^(-26)Am^(2)`

B

`8xx10^(-26)Am^(2)`

C

`9xx10^(-26)Am^(2)`

D

`6xx10^(-26)Am^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`M= i xx A =(f.e) pi r^(2) =(omega)/( 2pi). e.pi r^(2), ("ver")/(2)=M`
`:.M=(1.6 xx 10^(-19) xx 2 xx 10^(4) xx 5 xx 10^(-11))/(2) = 8xx 10^(-2) Am^(2) " " [T=(2pi r)/(v)]`
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