What is the sum of the divisors of 60 ?

Answer

To find the sum of the divisors of 60, we can follow these steps:

### Step 1: Identify the divisors of 60
First, we need to find all the numbers that can divide 60 without leaving a remainder. The divisors of 60 are:
- 1 (60 ÷ 1 = 60)
- 2 (60 ÷ 2 = 30)
- 3 (60 ÷ 3 = 20)
- 4 (60 ÷ 4 = 15)
- 5 (60 ÷ 5 = 12)
- 6 (60 ÷ 6 = 10)
- 10 (60 ÷ 10 = 6)
- 12 (60 ÷ 12 = 5)
- 15 (60 ÷ 15 = 4)
- 20 (60 ÷ 20 = 3)
- 30 (60 ÷ 30 = 2)
- 60 (60 ÷ 60 = 1)

So the complete list of divisors is: **1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60**.

### Step 2: Sum the divisors
Next, we add all the divisors together:
- 1 + 2 + 3 + 4 + 5 + 6 + 10 + 12 + 15 + 20 + 30 + 60

Calculating this step by step:
1. \(1 + 2 = 3\)
2. \(3 + 3 = 6\)
3. \(6 + 4 = 10\)
4. \(10 + 5 = 15\)
5. \(15 + 6 = 21\)
6. \(21 + 10 = 31\)
7. \(31 + 12 = 43\)
8. \(43 + 15 = 58\)
9. \(58 + 20 = 78\)
10. \(78 + 30 = 108\)
11. \(108 + 60 = 168\)

Thus, the sum of the divisors of 60 is **168**.

### Final Answer:
The sum of the divisors of 60 is **168**.

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