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What is the remainder when the product `1991xx1992xx2000` is divided by 7 ?

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To find the remainder when the product \( 1991 \times 1992 \times 2000 \) is divided by 7, we can follow these steps: ### Step 1: Find the remainders of each number when divided by 7 1. **Calculate \( 1991 \mod 7 \)**: - Divide \( 1991 \) by \( 7 \): - \( 1991 \div 7 = 284 \) remainder \( 3 \) (since \( 7 \times 284 = 1988 \) and \( 1991 - 1988 = 3 \)) - So, \( 1991 \equiv 3 \mod 7 \). 2. **Calculate \( 1992 \mod 7 \)**: - Since \( 1992 = 1991 + 1 \), we can find: - \( 1992 \equiv 3 + 1 \equiv 4 \mod 7 \). 3. **Calculate \( 2000 \mod 7 \)**: - Divide \( 2000 \) by \( 7 \): - \( 2000 \div 7 = 285 \) remainder \( 5 \) (since \( 7 \times 285 = 1995 \) and \( 2000 - 1995 = 5 \)) - So, \( 2000 \equiv 5 \mod 7 \). ### Step 2: Multiply the remainders Now we multiply the remainders we found: \[ (1991 \mod 7) \times (1992 \mod 7) \times (2000 \mod 7) \equiv 3 \times 4 \times 5 \mod 7 \] ### Step 3: Calculate \( 3 \times 4 \times 5 \) 1. First, calculate \( 3 \times 4 = 12 \). 2. Next, multiply \( 12 \times 5 = 60 \). ### Step 4: Find the remainder of \( 60 \) when divided by \( 7 \) Now we need to find \( 60 \mod 7 \): - Divide \( 60 \) by \( 7 \): - \( 60 \div 7 = 8 \) remainder \( 4 \) (since \( 7 \times 8 = 56 \) and \( 60 - 56 = 4 \)). - So, \( 60 \equiv 4 \mod 7 \). ### Final Answer Thus, the remainder when \( 1991 \times 1992 \times 2000 \) is divided by \( 7 \) is \( \boxed{4} \).
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