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(52)(7)+46(8)=(?)(10)...

`(52)_(7)+46_(8)=(?)_(10)`

A

`(75)_(10)`

B

`(50)_(10)`

C

`(39)_(39)`

D

`(28)_(10)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem `(52)_(7) + (46)_(8) = (?)_(10)`, we will convert both numbers from their respective bases to base 10, perform the addition, and then express the result in base 10. ### Step 1: Convert (52)_(7) to base 10 The number (52) in base 7 can be converted to base 10 using the formula: \[ \text{Value} = a \cdot x^1 + b \cdot x^0 \] where \( a \) and \( b \) are the digits of the number and \( x \) is the base. For (52)_(7): - \( a = 5 \) - \( b = 2 \) - \( x = 7 \) Calculating: \[ 5 \cdot 7^1 + 2 \cdot 7^0 = 5 \cdot 7 + 2 \cdot 1 = 35 + 2 = 37 \] ### Step 2: Convert (46)_(8) to base 10 Now, we convert (46) in base 8 to base 10 using the same formula. For (46)_(8): - \( a = 4 \) - \( b = 6 \) - \( x = 8 \) Calculating: \[ 4 \cdot 8^1 + 6 \cdot 8^0 = 4 \cdot 8 + 6 \cdot 1 = 32 + 6 = 38 \] ### Step 3: Add the two base 10 values Now, we add the two results from steps 1 and 2: \[ 37 + 38 = 75 \] ### Step 4: Write the final result in base 10 The result of the addition is \( 75 \) in base 10. Thus, the final answer is: \[ (52)_{7} + (46)_{8} = (75)_{10} \] ---
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