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Find the digit at the unit's place of ...

Find the digit at the unit's place of
`(377)^(59)xx(793)^(87)xx(578)^(129)xx(99)^(99)`

A

1

B

2

C

7

D

9

Text Solution

AI Generated Solution

The correct Answer is:
To find the digit at the unit's place of the expression \( (377)^{59} \times (793)^{87} \times (578)^{129} \times (99)^{99} \), we can follow these steps: ### Step 1: Identify the unit digits of each base - The unit digit of \( 377 \) is \( 7 \). - The unit digit of \( 793 \) is \( 3 \). - The unit digit of \( 578 \) is \( 8 \). - The unit digit of \( 99 \) is \( 9 \). ### Step 2: Rewrite the expression using only the unit digits We can rewrite the expression focusing on the unit digits: \[ (7^{59}) \times (3^{87}) \times (8^{129}) \times (9^{99}) \] ### Step 3: Determine the cyclicity of the unit digits - The unit digit of \( 7 \) has a cycle of \( 4 \): \( 7, 9, 3, 1 \). - The unit digit of \( 3 \) also has a cycle of \( 4 \): \( 3, 9, 7, 1 \). - The unit digit of \( 8 \) has a cycle of \( 4 \): \( 8, 4, 2, 6 \). - The unit digit of \( 9 \) has a cycle of \( 2 \): \( 9, 1 \) (odd powers yield \( 9 \), even powers yield \( 1 \)). ### Step 4: Calculate the effective powers modulo their cycles - For \( 7^{59} \): \[ 59 \mod 4 = 3 \quad \text{(since } 59 = 4 \times 14 + 3\text{)} \] Thus, the unit digit is \( 7^3 = 343 \) → unit digit is \( 3 \). - For \( 3^{87} \): \[ 87 \mod 4 = 3 \quad \text{(since } 87 = 4 \times 21 + 3\text{)} \] Thus, the unit digit is \( 3^3 = 27 \) → unit digit is \( 7 \). - For \( 8^{129} \): \[ 129 \mod 4 = 1 \quad \text{(since } 129 = 4 \times 32 + 1\text{)} \] Thus, the unit digit is \( 8^1 = 8 \). - For \( 9^{99} \): Since \( 99 \) is odd, the unit digit is \( 9 \). ### Step 5: Multiply the unit digits together Now we multiply the unit digits we found: \[ 3 \times 7 \times 8 \times 9 \] Calculating step by step: 1. \( 3 \times 7 = 21 \) → unit digit is \( 1 \). 2. \( 1 \times 8 = 8 \). 3. \( 8 \times 9 = 72 \) → unit digit is \( 2 \). ### Conclusion The unit digit of the entire expression \( (377)^{59} \times (793)^{87} \times (578)^{129} \times (99)^{99} \) is \( 2 \).
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