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A number which when divided by 32 leaves...

A number which when divided by 32 leaves a remainder of 29. If this number is divided by 8 the remainder will be

A

0

B

1

C

5

D

3

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The correct Answer is:
To solve the problem step by step, let's denote the unknown number as \( x \). ### Step 1: Understand the given information We know that when \( x \) is divided by 32, it leaves a remainder of 29. This can be expressed mathematically as: \[ x = 32k + 29 \] for some integer \( k \). ### Step 2: Find the value of \( x \) in terms of \( k \) From the equation above, we can see that \( x \) can take on multiple values depending on \( k \). However, we don't need the exact value of \( x \); we just need to find the remainder when \( x \) is divided by 8. ### Step 3: Substitute \( x \) into the division by 8 Now we need to find \( x \mod 8 \). We can substitute our expression for \( x \): \[ x = 32k + 29 \] ### Step 4: Simplify \( x \mod 8 \) To find \( x \mod 8 \), we can simplify: 1. First, calculate \( 32k \mod 8 \): \[ 32k \mod 8 = 0 \quad \text{(since 32 is a multiple of 8)} \] 2. Next, calculate \( 29 \mod 8 \): \[ 29 \div 8 = 3 \quad \text{(which gives a quotient of 3 and a remainder of 5)} \] Thus, \[ 29 \mod 8 = 5 \] ### Step 5: Combine results Now, we can combine the results: \[ x \mod 8 = (32k \mod 8 + 29 \mod 8) = (0 + 5) = 5 \] ### Conclusion Therefore, when the number \( x \) is divided by 8, the remainder is: \[ \boxed{5} \]
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