Home
Class 14
MATHS
(23)(5)+(47)(9)=(?)(8)...

`(23)_(5)+(47)_(9)=(?)_(8)`

A

70

B

35

C

64

D

18

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem `(23)_(5) + (47)_(9) = (?)_(8)`, we will follow these steps: ### Step 1: Convert (23)_(5) to Decimal To convert the base 5 number `23` to decimal, we use the formula: \[ \text{Decimal} = d_1 \times b^1 + d_0 \times b^0 \] where \( d_1 \) and \( d_0 \) are the digits of the number and \( b \) is the base. For `23` in base 5: - \( d_1 = 2 \) (the leftmost digit) - \( d_0 = 3 \) (the rightmost digit) - \( b = 5 \) Calculating: \[ 2 \times 5^1 + 3 \times 5^0 = 2 \times 5 + 3 \times 1 = 10 + 3 = 13 \] So, `(23)_(5)` in decimal is `13`. ### Step 2: Convert (47)_(9) to Decimal Next, we convert the base 9 number `47` to decimal using the same formula. For `47` in base 9: - \( d_1 = 4 \) - \( d_0 = 7 \) - \( b = 9 \) Calculating: \[ 4 \times 9^1 + 7 \times 9^0 = 4 \times 9 + 7 \times 1 = 36 + 7 = 43 \] So, `(47)_(9)` in decimal is `43`. ### Step 3: Add the Decimal Values Now we add the two decimal values obtained: \[ 13 + 43 = 56 \] ### Step 4: Convert the Sum (56) to Base 8 Finally, we need to convert `56` from decimal to base 8. We do this by dividing the number by 8 and keeping track of the remainders. 1. Divide `56` by `8`: - \( 56 \div 8 = 7 \) with a remainder of `0` 2. Divide `7` by `8`: - \( 7 \div 8 = 0 \) with a remainder of `7` Now we read the remainders from bottom to top, which gives us `70`. ### Final Answer Thus, the answer to the equation `(23)_(5) + (47)_(9) = (?)_(8)` is: \[ (70)_{8} \]
Promotional Banner

Topper's Solved these Questions

  • NUMBER SYSTEM

    DISHA PUBLICATION|Exercise Standard Level |45 Videos
  • NUMBER SYSTEM

    DISHA PUBLICATION|Exercise Expert Level |32 Videos
  • NUMBER SYSTEM

    DISHA PUBLICATION|Exercise Test Yourself|15 Videos
  • MOCK TEST 2

    DISHA PUBLICATION|Exercise Multiple Choice Questions|20 Videos
  • PERCENTAGES

    DISHA PUBLICATION|Exercise PRACTICE EXERCISE (TEST YOURSELF)|15 Videos

Similar Questions

Explore conceptually related problems

A point on the ellipse,4x^(2)+9y^(2)=36, where the normal is parallel to the line,4x-2y-5=0 is (A) ((8)/(5),-(9)/(5))(B)(-(9)/(5),(8)/(5))(C)((8)/(5),(9)/(5))(D)((9)/(5),(8)/(5))

Which property is being depicted in the expression provided below: (5)/(9) +[(-4)/(3)+((-9)/(8))]=[(5)/(9) +((-4)/(3))]-(9)/(8) .

If omega ne 1 is a complex cube root of unity, then 5.23 + omega + omega^(((1)/(2) + (3)/(8) + (9)/(32) + (27)/(128)+...)) is equal to __________

Simplify: [root(3)(root(6)(5^(9)))]^(8)[root(6)(root(3)(5^(9)))]^(8)

Solve ((5.9)^(3)+(1.8)^(3)+(4.8)^(3)-3xx5.9xx1.8xx4.8)/((5.9)^(2)+(1.8)^(2)+(4.8)^(2)-5.9xx1.8-1.8xx4.8-4.8xx5.9)

DISHA PUBLICATION-NUMBER SYSTEM-Practice Exercise (Foundation Level)
  1. The sum and number of even factors of 2450.

    Text Solution

    |

  2. Find the sum of divisors of 544 which are perfect squares.

    Text Solution

    |

  3. Find the number of zeroes in: 100^(1)xx99^(2)xx98^(3)xx97^(4)xx….xx1...

    Text Solution

    |

  4. (23)(5)+(47)(9)=(?)(8)

    Text Solution

    |

  5. LCM of first 100 natural numbers is N. What is the LCM of first 105 na...

    Text Solution

    |

  6. N! is completely divisible by 13^(52). What is sum of the digits of th...

    Text Solution

    |

  7. A two digit number is divided by the sum of its digits. What is the ma...

    Text Solution

    |

  8. 12^(55)//3^(11)+8^(48)//16^(18) will give the digit at units place as

    Text Solution

    |

  9. The unit digit in the expression 36^(234)"*"33^(512)"*"39^(180)-54^(...

    Text Solution

    |

  10. The last digit of the LCM of (3^(2003)-1)and(3^(2003)+1) is

    Text Solution

    |

  11. The persons start walking together and their steps measure 40 cm, 42 c...

    Text Solution

    |

  12. The sum of first n odd numbers (i.e., 1+3+5+7+…+2n-1) is divisible by ...

    Text Solution

    |

  13. Which of the following is/are true? (i) 43^(3)-1 is divisible by 11 ...

    Text Solution

    |

  14. The remainder when 6^(6^6^6^6^(..oo "times")) is divided by 10

    Text Solution

    |

  15. The last two-digits in the multiplication 122xx123xx125xx127xx129 wi...

    Text Solution

    |

  16. Find GCD (2^(120)-1,2^(100)-1).

    Text Solution

    |

  17. How many natural numbers are there which give a remainder of 41 after ...

    Text Solution

    |

  18. The remainder when 6^(6^6^6^6^(..oo "times")) is divided by 10

    Text Solution

    |

  19. Find the unit digit of the expression 199^(2n)+144^(3n), where n is a ...

    Text Solution

    |

  20. Simplify:- 256 * 24 ÷ 32 ÷ 3 = ?^2

    Text Solution

    |