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Find the number of even factors of 60060...

Find the number of even factors of 60060.

A

a) 128

B

b) 64

C

c) 32

D

d) 80

Text Solution

AI Generated Solution

The correct Answer is:
To find the number of even factors of 60060, we will follow these steps: ### Step 1: Prime Factorization of 60060 First, we need to find the prime factorization of 60060. 1. **Divide by 2 (the smallest prime number)**: - 60060 ÷ 2 = 30030 - 30030 ÷ 2 = 15015 (2 appears twice) 2. **Next, divide by 3**: - 15015 ÷ 3 = 5005 (3 appears once) 3. **Next, divide by 5**: - 5005 ÷ 5 = 1001 (5 appears once) 4. **Next, divide by 7**: - 1001 ÷ 7 = 143 (7 appears once) 5. **Next, divide by 11**: - 143 ÷ 11 = 13 (11 appears once) 6. **Finally, divide by 13**: - 13 ÷ 13 = 1 (13 appears once) So, the prime factorization of 60060 is: \[ 60060 = 2^2 \times 3^1 \times 5^1 \times 7^1 \times 11^1 \times 13^1 \] ### Step 2: Finding the Total Number of Factors To find the total number of factors, we use the formula: \[ (e_1 + 1)(e_2 + 1)(e_3 + 1)...(e_n + 1) \] where \( e_i \) are the powers of the prime factors. From our factorization: - The powers are: \( 2^2, 3^1, 5^1, 7^1, 11^1, 13^1 \) Calculating the total number of factors: \[ (2 + 1)(1 + 1)(1 + 1)(1 + 1)(1 + 1)(1 + 1) \] \[ = 3 \times 2 \times 2 \times 2 \times 2 \times 2 \] \[ = 3 \times 2^5 \] \[ = 3 \times 32 = 96 \] ### Step 3: Finding the Number of Even Factors To find the number of even factors, we note that an even factor must include at least one factor of 2. 1. **Consider the prime factorization without the factor of 2**: - The remaining factors are: \( 3^1, 5^1, 7^1, 11^1, 13^1 \) 2. **Calculating the number of factors of the remaining part**: \[ (1 + 1)(1 + 1)(1 + 1)(1 + 1)(1 + 1) \] \[ = 2 \times 2 \times 2 \times 2 \times 2 \] \[ = 2^5 = 32 \] 3. **Since each of these factors can be multiplied by the factors of \( 2^2 \)**: - The number of even factors is: \[ 32 \times 2 = 64 \] ### Final Answer The number of even factors of 60060 is **64**. ---
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