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Ram prepares solutions of alcohol in wat...

Ram prepares solutions of alcohol in water according to customers' needs. This morning Ram has prepared 27 litres of a 12% alcohol solution and kept it ready in a 27 litre delivery container to be shipped to the customer. Just before delivery, he finds out that the customer had asked for 27 litres of 21% alcohol solution. To prepare what the customer u wants, Ram replaces a portion of 12% solution by 39% solution. How many litres of 12% solution are replaced?

A

5

B

9

C

10

D

12

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine how many liters of the 12% alcohol solution Ram needs to replace with the 39% alcohol solution in order to create a final solution that is 27 liters of 21% alcohol. ### Step-by-Step Solution: 1. **Define the Variables**: Let \( x \) be the amount (in liters) of the 12% solution that Ram replaces with the 39% solution. 2. **Calculate the Amount of Alcohol in the Original Solution**: The original 27 liters of 12% solution contains: \[ \text{Alcohol from 12% solution} = 27 \times \frac{12}{100} = 3.24 \text{ liters} \] 3. **Calculate the Amount of Alcohol in the New Solution**: After replacing \( x \) liters of the 12% solution with \( x \) liters of the 39% solution, the amount of alcohol in the new solution will be: - Alcohol from the remaining 12% solution: \[ \text{Remaining 12% alcohol} = (27 - x) \times \frac{12}{100} = \frac{12(27 - x)}{100} \] - Alcohol from the 39% solution: \[ \text{Alcohol from 39% solution} = x \times \frac{39}{100} = \frac{39x}{100} \] 4. **Set Up the Equation for the Final Solution**: The total amount of alcohol in the final solution must equal the amount of alcohol in 27 liters of 21% solution: \[ \text{Total alcohol in final solution} = \frac{12(27 - x)}{100} + \frac{39x}{100} \] The amount of alcohol in 27 liters of 21% solution is: \[ 27 \times \frac{21}{100} = 5.67 \text{ liters} \] 5. **Equate and Solve the Equation**: Set the total alcohol from the new solution equal to the alcohol in the 21% solution: \[ \frac{12(27 - x)}{100} + \frac{39x}{100} = 5.67 \] Multiply through by 100 to eliminate the fraction: \[ 12(27 - x) + 39x = 567 \] Expanding gives: \[ 324 - 12x + 39x = 567 \] Combine like terms: \[ 27x + 324 = 567 \] Subtract 324 from both sides: \[ 27x = 243 \] Divide by 27: \[ x = 9 \] 6. **Conclusion**: Ram needs to replace **9 liters** of the 12% solution with the 39% solution.
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