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There are two mixtures of honey and wate...

There are two mixtures of honey and water, the quantity of honey in them being 25% and 75% of the mixture. If 2 gallons of the first are mixed with three gallons of the second, what will be the ratio of honey to water in the new mixture?

A

`11:2`

B

`11:9`

C

`9:11`

D

`2:11`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the ratio of honey to water in the new mixture created by combining two different mixtures of honey and water. ### Step-by-Step Solution: 1. **Identify the Mixtures**: - The first mixture has 25% honey and 75% water. - The second mixture has 75% honey and 25% water. 2. **Convert Percentages to Fractions**: - 25% can be expressed as \( \frac{1}{4} \) (honey) and \( \frac{3}{4} \) (water) for the first mixture. - 75% can be expressed as \( \frac{3}{4} \) (honey) and \( \frac{1}{4} \) (water) for the second mixture. 3. **Calculate the Amounts in Each Mixture**: - For the first mixture (2 gallons): - Honey = \( 25\% \) of 2 gallons = \( 0.25 \times 2 = 0.5 \) gallons - Water = \( 75\% \) of 2 gallons = \( 0.75 \times 2 = 1.5 \) gallons - For the second mixture (3 gallons): - Honey = \( 75\% \) of 3 gallons = \( 0.75 \times 3 = 2.25 \) gallons - Water = \( 25\% \) of 3 gallons = \( 0.25 \times 3 = 0.75 \) gallons 4. **Combine the Amounts**: - Total Honey = Honey from first mixture + Honey from second mixture - Total Honey = \( 0.5 + 2.25 = 2.75 \) gallons - Total Water = Water from first mixture + Water from second mixture - Total Water = \( 1.5 + 0.75 = 2.25 \) gallons 5. **Calculate the Ratio of Honey to Water**: - Ratio of Honey to Water = Total Honey : Total Water - Ratio = \( 2.75 : 2.25 \) 6. **Simplify the Ratio**: - To simplify, we can divide both sides by 0.25: - \( \frac{2.75}{0.25} : \frac{2.25}{0.25} = 11 : 9 \) ### Final Answer: The ratio of honey to water in the new mixture is **11:9**. ---
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