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A and B can do a certain piece of work i...

A and B can do a certain piece of work in 8 days, B and C can do it in 12 days and C and A can do it in 24 days. How long would B take separately to do it ?

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To solve the problem, we need to find out how long B would take to complete the work alone. We will start by determining the work rates of A, B, and C based on the information provided. ### Step 1: Determine the work rates of A, B, and C 1. **A and B together can complete the work in 8 days.** - Work done by A and B in one day = \( \frac{1}{8} \) of the work. 2. **B and C together can complete the work in 12 days.** - Work done by B and C in one day = \( \frac{1}{12} \) of the work. 3. **C and A together can complete the work in 24 days.** - Work done by C and A in one day = \( \frac{1}{24} \) of the work. ### Step 2: Set up equations based on the work rates Let: - Work rate of A = \( a \) - Work rate of B = \( b \) - Work rate of C = \( c \) From the information above, we can set up the following equations: 1. \( a + b = \frac{1}{8} \) (Equation 1) 2. \( b + c = \frac{1}{12} \) (Equation 2) 3. \( c + a = \frac{1}{24} \) (Equation 3) ### Step 3: Solve the equations We can add all three equations together: \[ (a + b) + (b + c) + (c + a) = \frac{1}{8} + \frac{1}{12} + \frac{1}{24} \] This simplifies to: \[ 2a + 2b + 2c = \frac{1}{8} + \frac{1}{12} + \frac{1}{24} \] ### Step 4: Find a common denominator The least common multiple of 8, 12, and 24 is 24. We convert each fraction: \[ \frac{1}{8} = \frac{3}{24}, \quad \frac{1}{12} = \frac{2}{24}, \quad \frac{1}{24} = \frac{1}{24} \] Now, we can add them: \[ \frac{3}{24} + \frac{2}{24} + \frac{1}{24} = \frac{6}{24} = \frac{1}{4} \] ### Step 5: Substitute back to find \( a + b + c \) From the equation \( 2a + 2b + 2c = \frac{1}{4} \), we divide by 2: \[ a + b + c = \frac{1}{8} \] ### Step 6: Find individual work rates Now we can express \( c \) in terms of \( a \) and \( b \): From Equation 1: \[ c = \frac{1}{12} - b \] Substituting \( c \) into Equation 3: \[ \frac{1}{12} - b + a = \frac{1}{24} \] Rearranging gives us: \[ a - b = \frac{1}{24} - \frac{1}{12} = \frac{1}{24} - \frac{2}{24} = -\frac{1}{24} \] So, \( a = b - \frac{1}{24} \). ### Step 7: Substitute \( a \) into Equation 1 Substituting \( a \) back into Equation 1: \[ (b - \frac{1}{24}) + b = \frac{1}{8} \] This simplifies to: \[ 2b - \frac{1}{24} = \frac{3}{24} \] Adding \( \frac{1}{24} \) to both sides: \[ 2b = \frac{4}{24} = \frac{1}{6} \] Dividing by 2: \[ b = \frac{1}{12} \] ### Step 8: Find the time taken by B alone Since \( b \) is the work rate of B, the time taken by B to complete the work alone is the reciprocal of \( b \): \[ \text{Time taken by B} = \frac{1}{b} = \frac{1}{\frac{1}{12}} = 12 \text{ days} \] ### Final Answer B would take **12 days** to complete the work alone. ---
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