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In a certain factory, each day the expec...

In a certain factory, each day the expected number of accidents is related to the number of overtime hours by a linear equation. Suppose that on one day there were 1000 overtime hours logged and 8 accidents reported and on another day, there were 400 overtime hours logged and 5 accidents. What are the expected number of accidents when no overtime hours are logged?

A

2

B

3

C

4

D

5

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AI Generated Solution

The correct Answer is:
To solve the problem, we need to establish the relationship between the number of overtime hours and the number of accidents using a linear equation. We will denote the number of overtime hours as \( X \) and the number of accidents as \( A \). The linear equation can be expressed as: \[ A = mX + C \] where \( m \) is the slope of the line and \( C \) is the y-intercept (the expected number of accidents when no overtime hours are logged). ### Step 1: Set up the equations based on the given data. From the problem, we have two data points: 1. When \( X = 1000 \) hours, \( A = 8 \) accidents. 2. When \( X = 400 \) hours, \( A = 5 \) accidents. We can set up the following equations based on these points: 1. \( 8 = 1000m + C \) (Equation 1) 2. \( 5 = 400m + C \) (Equation 2) ### Step 2: Subtract the two equations to eliminate \( C \). To find \( m \), we can subtract Equation 2 from Equation 1: \[ (8 - 5) = (1000m + C) - (400m + C) \] This simplifies to: \[ 3 = 600m \] ### Step 3: Solve for \( m \). Now, we can solve for \( m \): \[ m = \frac{3}{600} = \frac{1}{200} \] ### Step 4: Substitute \( m \) back into one of the original equations to find \( C \). We can substitute \( m \) back into Equation 1 to find \( C \): \[ 8 = 1000 \left(\frac{1}{200}\right) + C \] This simplifies to: \[ 8 = 5 + C \] So, \[ C = 8 - 5 = 3 \] ### Step 5: Write the final equation. Now we have both \( m \) and \( C \): \[ A = \frac{1}{200}X + 3 \] ### Step 6: Find the expected number of accidents when no overtime hours are logged. When no overtime hours are logged, \( X = 0 \): \[ A = \frac{1}{200}(0) + 3 = 3 \] Thus, the expected number of accidents when no overtime hours are logged is **3**. ---
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