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Let f (x) = |x – 2| + |x – 3| + |x – 4| ...

Let `f (x) = |x – 2| + |x – 3| + |x – 4| and g(x) = f (x + 1)`. Then

A

g(x) is an even function

B

g(x) is an odd function

C

g(x) is neither even nor odd

D

None of these

Text Solution

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The correct Answer is:
C
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