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There are n different books and p copies...

There are n different books and p copies of each in a library. Find the number of ways in which one or more than one books can be selected.

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To find the number of ways to select one or more books from a library containing \( n \) different books, each with \( p \) copies, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Selection Process**: Each book can be selected in several ways: - You can choose not to select any copy of the book (0 copies). - You can select 1 copy of the book. - You can select 2 copies of the book. - ... - You can select up to \( p \) copies of the book. Thus, for each book, the number of ways to select copies is \( p + 1 \) (including the option of selecting 0 copies). 2. **Calculating Total Selections for All Books**: Since there are \( n \) different books and the selection of each book is independent of the others, the total number of ways to select books (including the option of selecting none) is: \[ (p + 1)^n \] This accounts for all combinations of selections across all \( n \) books. 3. **Excluding the Case of Selecting No Books**: The above calculation includes the scenario where none of the books are selected (i.e., selecting 0 copies of each book). Since we want to find the number of ways to select **one or more** books, we need to subtract this one case from our total: \[ \text{Total selections of one or more books} = (p + 1)^n - 1 \] ### Final Answer: Thus, the number of ways in which one or more than one book can be selected is: \[ (p + 1)^n - 1 \]
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