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The last time Raman was buying Deepawali...

The last time Raman was buying Deepawali cards, he found four types of cards that he liked priced at Rs. 2.00, Rs.3.50, Rs.4.50 and Rs.5.00 each. As Raman wanted 30 cards he took five each of two kinds and ten each of other two putting down the exact number of ten rupee notes on the counter for payment. How many notes did Raman pay?

A

8

B

9

C

10

D

11

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to calculate the total cost of the cards Raman bought and then determine how many Rs. 10 notes he used for payment. ### Step-by-Step Solution: 1. **Identify the Prices of the Cards:** - Type 1: Rs. 2.00 - Type 2: Rs. 3.50 - Type 3: Rs. 4.50 - Type 4: Rs. 5.00 2. **Determine the Quantity of Each Type of Card:** - Raman bought 5 cards of two types and 10 cards of the other two types. - Let's assume he bought: - 5 cards of Type 2 (Rs. 3.50) - 5 cards of Type 3 (Rs. 4.50) - 10 cards of Type 1 (Rs. 2.00) - 10 cards of Type 4 (Rs. 5.00) 3. **Calculate the Total Cost:** - Cost of 10 cards of Type 1 (Rs. 2.00): \[ 10 \times 2 = 20 \text{ Rs.} \] - Cost of 5 cards of Type 2 (Rs. 3.50): \[ 5 \times 3.5 = 17.5 \text{ Rs.} \] - Cost of 5 cards of Type 3 (Rs. 4.50): \[ 5 \times 4.5 = 22.5 \text{ Rs.} \] - Cost of 10 cards of Type 4 (Rs. 5.00): \[ 10 \times 5 = 50 \text{ Rs.} \] 4. **Sum Up All the Costs:** \[ \text{Total Cost} = 20 + 17.5 + 22.5 + 50 = 110 \text{ Rs.} \] 5. **Calculate the Number of Rs. 10 Notes:** - To find out how many Rs. 10 notes are needed to pay Rs. 110: \[ \text{Number of notes} = \frac{110}{10} = 11 \text{ notes.} \] ### Final Answer: Raman paid **11 Rs. 10 notes**.
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