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If `cos (theta - alpha) = a, cos (theta - beta) = b`, then the value of ` sin^(2) (alpha - beta) + 2ab cos (alpha - beta)` is

A

`a^2+b^2`

B

`a^2-b^2`

C

`b^2-a^2`

D

`-(a^2+b^2)`

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The correct Answer is:
A
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