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If cos A = 3//4 . then what is the value...

If cos A = `3//4` . then what is the value of sin`((A)/(2))sin((3A)/(2))` ?

A

`5//8`

B

`5//16`

C

`5//24`

D

`7//32`

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The correct Answer is:
To solve the problem, we need to find the value of \( \sin\left(\frac{A}{2}\right) \sin\left(\frac{3A}{2}\right) \) given that \( \cos A = \frac{3}{4} \). ### Step-by-Step Solution: 1. **Use the Product-to-Sum Formula:** We can use the identity: \[ \sin c \sin d = \frac{1}{2} \left( \cos(c - d) - \cos(c + d) \right) \] Here, let \( c = \frac{A}{2} \) and \( d = \frac{3A}{2} \). 2. **Calculate \( c - d \) and \( c + d \):** - \( c - d = \frac{A}{2} - \frac{3A}{2} = -A \) - \( c + d = \frac{A}{2} + \frac{3A}{2} = 2A \) 3. **Substituting into the Identity:** Now substituting these values into the identity: \[ \sin\left(\frac{A}{2}\right) \sin\left(\frac{3A}{2}\right) = \frac{1}{2} \left( \cos(-A) - \cos(2A) \right) \] Since \( \cos(-A) = \cos A \), we have: \[ \sin\left(\frac{A}{2}\right) \sin\left(\frac{3A}{2}\right) = \frac{1}{2} \left( \cos A - \cos(2A) \right) \] 4. **Finding \( \cos(2A) \):** We can use the double angle formula: \[ \cos(2A) = 2\cos^2 A - 1 \] Given \( \cos A = \frac{3}{4} \): \[ \cos(2A) = 2\left(\frac{3}{4}\right)^2 - 1 = 2 \cdot \frac{9}{16} - 1 = \frac{18}{16} - 1 = \frac{18}{16} - \frac{16}{16} = \frac{2}{16} = \frac{1}{8} \] 5. **Substituting Back:** Now substitute \( \cos A \) and \( \cos(2A) \) back into our equation: \[ \sin\left(\frac{A}{2}\right) \sin\left(\frac{3A}{2}\right) = \frac{1}{2} \left( \frac{3}{4} - \frac{1}{8} \right) \] 6. **Finding a Common Denominator:** To subtract \( \frac{3}{4} \) and \( \frac{1}{8} \), we need a common denominator: \[ \frac{3}{4} = \frac{6}{8} \] So, \[ \frac{3}{4} - \frac{1}{8} = \frac{6}{8} - \frac{1}{8} = \frac{5}{8} \] 7. **Final Calculation:** Now substitute this back into our equation: \[ \sin\left(\frac{A}{2}\right) \sin\left(\frac{3A}{2}\right) = \frac{1}{2} \cdot \frac{5}{8} = \frac{5}{16} \] ### Final Answer: Thus, the value of \( \sin\left(\frac{A}{2}\right) \sin\left(\frac{3A}{2}\right) \) is \( \frac{5}{16} \).
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