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What is sin^2 66 (1^@)/(2)-sin^2 23(1^@)...

What is `sin^2 66 (1^@)/(2)-sin^2 23(1^@)/(2)` equal to:

A

`sin47^@`

B

`cos47^@`

C

`2sin47^@`

D

`2cos47^@`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \( \sin^2 66.5^\circ - \sin^2 23.5^\circ \), we can use trigonometric identities to simplify it step by step. ### Step 1: Rewrite the sine function We know that: \[ \sin^2 A = 1 - \cos^2 A \] Thus, we can rewrite \( \sin^2 66.5^\circ \) and \( \sin^2 23.5^\circ \): \[ \sin^2 66.5^\circ = 1 - \cos^2 66.5^\circ \] \[ \sin^2 23.5^\circ = 1 - \cos^2 23.5^\circ \] ### Step 2: Substitute into the expression Now substituting these into the original expression: \[ \sin^2 66.5^\circ - \sin^2 23.5^\circ = (1 - \cos^2 66.5^\circ) - (1 - \cos^2 23.5^\circ) \] This simplifies to: \[ \sin^2 66.5^\circ - \sin^2 23.5^\circ = -\cos^2 66.5^\circ + \cos^2 23.5^\circ \] ### Step 3: Use the identity for the difference of squares We can use the identity for the difference of squares: \[ a^2 - b^2 = (a - b)(a + b) \] Let \( a = \cos 23.5^\circ \) and \( b = \cos 66.5^\circ \): \[ \cos^2 23.5^\circ - \cos^2 66.5^\circ = (\cos 23.5^\circ - \cos 66.5^\circ)(\cos 23.5^\circ + \cos 66.5^\circ) \] ### Step 4: Calculate the angles Using the cosine addition formulas, we can find: \[ \cos 66.5^\circ = \sin(90^\circ - 66.5^\circ) = \sin 23.5^\circ \] Thus: \[ \cos 23.5^\circ - \cos 66.5^\circ = \cos 23.5^\circ - \sin 23.5^\circ \] And: \[ \cos 23.5^\circ + \cos 66.5^\circ = \cos 23.5^\circ + \sin 23.5^\circ \] ### Step 5: Final expression Putting it all together, we can express the original difference as: \[ \sin^2 66.5^\circ - \sin^2 23.5^\circ = (\cos 23.5^\circ - \sin 23.5^\circ)(\cos 23.5^\circ + \sin 23.5^\circ) \] ### Conclusion Thus, the expression \( \sin^2 66.5^\circ - \sin^2 23.5^\circ \) simplifies to: \[ (\cos 23.5^\circ - \sin 23.5^\circ)(\cos 23.5^\circ + \sin 23.5^\circ) \]
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PUNEET DOGRA-TRIGONOMETRY-PREV YEAR QUESTIONS
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