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What is the value of (1+sinA)/(1-sinA)-(...

What is the value of `(1+sinA)/(1-sinA)-(1-sinA)/(1+sinA)`?

A

sec A - tan A

B

2sec A tan A

C

4sec A. tan A

D

4cosec A.cot A

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The correct Answer is:
To solve the expression \((1 + \sin A)/(1 - \sin A) - (1 - \sin A)/(1 + \sin A)\), we will follow these steps: ### Step 1: Find a common denominator The common denominator for the two fractions is \((1 - \sin A)(1 + \sin A)\). ### Step 2: Rewrite the expression We can rewrite the expression as: \[ \frac{(1 + \sin A)^2 - (1 - \sin A)^2}{(1 - \sin A)(1 + \sin A)} \] ### Step 3: Expand the numerators Now, we will expand the numerators: \[ (1 + \sin A)^2 = 1 + 2\sin A + \sin^2 A \] \[ (1 - \sin A)^2 = 1 - 2\sin A + \sin^2 A \] ### Step 4: Subtract the expanded forms Now we subtract the two expanded forms: \[ (1 + 2\sin A + \sin^2 A) - (1 - 2\sin A + \sin^2 A) \] This simplifies to: \[ 1 + 2\sin A + \sin^2 A - 1 + 2\sin A - \sin^2 A = 4\sin A \] ### Step 5: Substitute back into the fraction Now we substitute back into the fraction: \[ \frac{4\sin A}{(1 - \sin A)(1 + \sin A)} \] ### Step 6: Simplify the denominator The denominator can be simplified using the difference of squares: \[ (1 - \sin A)(1 + \sin A) = 1 - \sin^2 A = \cos^2 A \] ### Step 7: Final expression Now we have: \[ \frac{4\sin A}{\cos^2 A} \] This can be rewritten as: \[ 4\sec^2 A \cdot \sin A \] ### Step 8: Express in terms of tan Since \(\tan A = \frac{\sin A}{\cos A}\), we can express this as: \[ 4\sec A \cdot \tan A \] ### Conclusion Thus, the final value of the expression is: \[ 4\sec A \cdot \tan A \]
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