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PT. a tower of height 2^(x) metre, P be...

PT. a tower of height `2^(x)` metre, P being the foot. T being the top of the tower. A, B are points on the same line with P. If `AP = 2^(x+1)m. BP = 192 m` and if the angle of elevation of the tower as seen from b is double the angle of the elevation of the tower as seen from A, then what is the value of x?

A

A. 6

B

B. 7

C

C. 8

D

D. 9

Text Solution

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The correct Answer is:
To solve the problem step by step, we will follow the given information and apply trigonometric principles to find the value of \( x \). ### Step 1: Understand the Problem We have a tower \( PT \) with height \( 2^x \) meters, where \( P \) is the foot of the tower. The distance from point \( A \) to point \( P \) is \( AP = 2^{x+1} \) meters, and the distance from point \( B \) to point \( P \) is \( BP = 192 \) meters. The angle of elevation from point \( B \) is double that from point \( A \). ### Step 2: Set Up the Angles Let the angle of elevation from point \( A \) be \( \theta \). Therefore, the angle of elevation from point \( B \) will be \( 2\theta \). ### Step 3: Use Triangle \( PTA \) In triangle \( PTA \): - The height \( PT = 2^x \) (the height of the tower). - The base \( AP = 2^{x+1} \). Using the tangent function: \[ \tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} = \frac{2^x}{2^{x+1}} = \frac{2^x}{2^x \cdot 2} = \frac{1}{2} \] This gives us our first equation: \[ \tan(\theta) = \frac{1}{2} \] ### Step 4: Use Triangle \( PTB \) In triangle \( PTB \): - The height \( PT = 2^x \). - The base \( BP = 192 \). Using the tangent function: \[ \tan(2\theta) = \frac{2^x}{192} \] ### Step 5: Use the Double Angle Formula We know from trigonometry that: \[ \tan(2\theta) = \frac{2\tan(\theta)}{1 - \tan^2(\theta)} \] Substituting \( \tan(\theta) = \frac{1}{2} \): \[ \tan(2\theta) = \frac{2 \cdot \frac{1}{2}}{1 - \left(\frac{1}{2}\right)^2} = \frac{1}{1 - \frac{1}{4}} = \frac{1}{\frac{3}{4}} = \frac{4}{3} \] ### Step 6: Set Up the Equation Now we can set up the equation using the value of \( \tan(2\theta) \): \[ \frac{4}{3} = \frac{2^x}{192} \] ### Step 7: Solve for \( 2^x \) Cross-multiplying gives: \[ 4 \cdot 192 = 3 \cdot 2^x \] Calculating \( 4 \cdot 192 \): \[ 768 = 3 \cdot 2^x \] Dividing both sides by 3: \[ 2^x = \frac{768}{3} = 256 \] ### Step 8: Solve for \( x \) Recognizing that \( 256 = 2^8 \): \[ 2^x = 2^8 \implies x = 8 \] ### Final Answer The value of \( x \) is \( 8 \). ---
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